In the reaction, 2Al (s) + 6HCl (aq)

• Stoichiometry

In the reaction,

2Al (s) + 6HCl (aq) → 2Al³⁺ (aq) + 6Cl^– (aq) + 3H₂ (g)

1. 6 L HCl (aq) is consumed for every 3 L H₂(g) produced
2. 11.2 L H₂(g) at STP is produced for every mole HCl (aq) consumed
3. 33.6 L H₂(g) is produced regardless of temperature and pressure for every mole Al that reacts
4. 67.2 L H₂(g) at STP is produced for every mole Al that reacts

Answer

2Al (s) + 6HCl (aq) → 2Al³⁺ (aq) + 6Cl^– (aq) + 3H₂ (g)

At STP, 6 moles of HCl produces 3 moles or 3 × 22.4 lit of HCl

1 mole of HCl produces 3*22.4/6 = 11.2 lit of HCl

Again at STP, 2 moles of Al produces 3 moles or 3 × 22.4 lit of HCl

or 1 mole of Al produces 3*22.4/2= 33.6 lit of HCl

The correct option is C.