Let A and B be two sets containing four and two elements respectively
Let A and B be two sets containing four and two elements respectively. Then the number of subsets of the set A × B, each having at least three elements is
- 510
- 256
- 275
- 219
Solution
n(A) = 4
n(B) = 2
n(A × B) = 8
So atleast 3 = total – none – one – two digits
= 28 – 1 – 8C1 – 8C2 = 28 – 1 – 8 – 28 = 28 – 37
= 256 – 37 = 219
The correct option is D.