A boy can throw a stone up to a maximum height of 10 m
A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be
- 10 m
- 20√2 m
- 20 m
- 10√2 m
Answer
Maximum vertical height = u2/2g = 10 m
Horizontal range of a projectile = u2 sin2θ/g
Range is maximum when θ = 45°
Maximum horizontal range = u2/g
Hence, maximum horizontal distance = 20 m
The correct option is C.