The Number of complex numbers z such that |z – 1| = |z + 1| = |z – i| equals

The Number of complex numbers z such that |z – 1| = |z + 1| = |z – i| equals

  1. 0
  2. 1
  3. 2
  4. infinity

Solution

~ |z – 1| = |z + 1|

lies on y-axis (perpendicular bisector of the line segment joining (0, 1) and (0, -1)

~ |z + 1| = |z – 1|

lies on y = -x

The correct option is B.