The Number of complex numbers z such that |z – 1| = |z + 1| = |z – i| equals
The Number of complex numbers z such that |z – 1| = |z + 1| = |z – i| equals
- 0
- 1
- 2
- infinity
Solution
~ |z – 1| = |z + 1|
lies on y-axis (perpendicular bisector of the line segment joining (0, 1) and (0, -1)
~ |z + 1| = |z – 1|
lies on y = -x
The correct option is B.